In ∆ABC and ∆PQR, it is given that AB=AC, ∠C=∠P and ∠P=∠Q. Then, the two triangles are
It is given in the question that,
In ∆ABC and ∆PQR, we have
AB = AC
Also, ∠C = ∠B
As, ∠C = ∠P and, ∠B = ∠Q
∴ ∠P = ∠Q
So, both triangles are isosceles but not congruent
Hence, option (A) is correct