In the given figure, it is given that AD=BC and AC=BD.

Prove that CAD=CBD and ADC=BCD.


From the given figure,

In triangles DAC and CBD, we have:


AD = BC


AC = BD


DC = DC


So, by SSS congruence rule


∆ADC BCD


By Congruent parts of congruent triangles we have:


CAD = CBD


ADC = BCD


ACD = BDC


Hence, proved


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