In the given figure, PQ>PR and QS and RS are the bisectors of ∠Q and ∠R respectively. Show that SQ>SR
It is given in the question that,
PQ > PR
And, QS and RS are the bisectors of ∠ Q and ∠ R
We have, angle opposite to the longer side is greater
∴ PQ > PR
∠ R > ∠ Q
∠ SRQ > ∠ RQS
SQ > SR
Hence, proved