(a) Steps of Construction-

1. Draw a ray OA

2. Taking O as centre and convenient radius, mark an arc, which intersects OA at P.

3. Taking P as centre and same radius, cut previous arc at Q. Join OQ. Thus, ∠BOA is required angle of 60°

(b) Steps of Construction-

1. Draw a ray OA.

2. Taking O as centre and convenient radius, mark an arc, which intersects OA at P.

3. Taking P as centre and same radius, cut previous arc at Q. Join OQ. Thus, ∠BOA is required angle of 60°.

4. Put the pointer on P and mark an arc.

5. Put the pointer on Q and with same radius, cut the previous arc at C. Thus, ∠COA is required angle of 30°

(c) Steps of Construction-

1. Draw a ray OA

2. Taking O as centre and convenient radius, mark an arc, which intersects OA at X.

3. Taking X as centre and same radius, cut previous arc at Y. Taking Y as centre and same radius, draw another arc intersecting the same arc at Z.

4. Taking Y and Z as centers and same radius, draw two arcs intersecting each other at S.

5. Join OS. Thus, ∠SOA is required angle of 90°

(d) Steps of Construction-

1. Draw a ray OA

2. Taking O as centre and convenient radius, mark an arc, which intersects OA at P.

3. Taking P as centre and same radius, cut previous arc at Q. Taking Q as centre and same radius cut the arc at S. Join OS.

Thus, ∠AOS is required angle of 120°.

(e) Steps of Construction-

1. Draw a ray OA

2. Taking O as centre and convenient radius, mark an arc, which intersects OA at X.

3. Taking X as centre and same radius, cut previous arc at Y. Taking Y as centre and same radius, draw another arc intersecting the same arc at Z.

4. Taking Y and Z as centers and same radius, draw two arcs intersecting each other at S. Join OS. Thus, ∠SOA is required angle of 90°.

5. Draw the bisector of SOA. Hence, ∠MOA = 45°

(f) Steps of Construction-

1. Draw a line PQ and take a point O on it.

2. Taking O as centre and convenient radius, mark an arc, which intersects PQ at A and B.

3. Taking A and B as centers and radius more than half of AB, draw two arcs intersecting each other at R. Join OR. Thus, ∠QOR = ∠POR = 90°.

4. Draw OD the bisector of ∠POR. Thus, ∠QOD is required angle of 135°

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