In the given figure, CE || BA and EF || CD. If BAC = 40°, ACB = 65° and CEF = x° then the value of x is

Given,

BAC = 40°


ACB = 65°


According to figure,


ACE = 40° [Alternate angles]


ACB + ACE = x° [Alternate angles]


x° = 65° + 40°


x = 105°

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