In the given figure, CE || BA and EF || CD. If ∠BAC = 40°, ∠ACB = 65° and ∠CEF = x° then the value of x is
Given,
∠BAC = 40°
∠ACB = 65°
According to figure,
⸫ ∠ACE = 40° [Alternate angles]
⸫ ∠ACB + ∠ACE = x° [Alternate angles]
⇒ x° = 65° + 40°
⸫ x = 105°