In a ΔABC, if A - B = 33° and B - C = 18°, find the measure of each angle of the triangle.

Let the three angles of a triangle be A, B, C

Given, A - B = 33°


A = B + 33°


B - C = 18°


C = B 18°


Now,


A + B + C = 180° [Sum of all angles of a triangle = 180°]


B + 33° + B + B 18° = 180°


3B = 180° - 15°


B = 55°


A = B + 33° = 88°


C = B 18° = 37°


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