In the given figure, AM BC and AN is the bisector of A. If ABC = 70° and ACB = 20°, find MAN.

In ΔABC,

A = 180° - 70° - 20° [Sum of all angles of a triangle = 180°]


A = 90°


BAN = 45° [ AN is the bisector of A]


In ΔABN,


N = 180° - 70° - 45° [Sum of all angles of a triangle = 180°]


N = 65°


In ΔAMN,


MAN = 180° - 90° - 65° [Sum of all angles of a triangle = 180°]


MAN = 25°


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