An object of 5.0 cm size is placed at a distance of 20.0 cm from a converging mirror of radius of curvature 30.0 cm. At what distance from the mirror should a screen be placed to get the sharp image ? Also calculate the size of the image.

Radius of curvature = 30.0 cm

F = R/2 = 30/2 = 15 cm



The screen should be placed 60 cm in front of the mirror.


And



23