If one of the zeroes of the quadratic polynomial (k - 1) x2 + kx + 1 is - 3, then the value of k is
Zeroes of a polynomial is all the values of x at which the polynomial is equal to zero. Therefore, for the polynomial p(x) = (k - 1) x2 + kx + 1 ie.
p (- 3) = 0
(k - 1)(- 3)2 + k(- 3) + 1 = 0
(k - 1)(9) - 3k + 1 = 0
9k - 3k - 8 = 0
6k = 8
k = 4/3