If two of the zeroes of cubic polynomials are zero then it does not have linear and constant terms: True

Let α, β and γ be the zeroes of the polynomial p(x0 = ax³ + bx² + cx + d, where given α = β = 0

Clearly a≠ 0

Product of all zeroes = - (constant term) ÷ coefficient of x³

αβγ = - d/a

0 = - d/a

⇒ d = 0 (no constant term)

∴ the polynomial is p(x) = ax³ + bx² + cx

Sum of the products of two zeroes at a time = coefficient of x ÷ coefficient of x³

αβ + βγ + αγ = c/a

0 + (0) γ + (0) γ = c/a

0 = c/a

⇒ c = 0 (no linear term)

∴ the polynomial is p(x) = ax³ + bx²

Sum of the zeroes = - (coefficient of x²) ÷ coefficient of x³

α + β + γ = - b/a

0 + 0 + γ = - b/a

⇒ b = - γ/a (there exists x² term ∵ b≠ 0)

∴ the polynomial is p(x) = ax³ - γx²/a

Hence, the polynomial does not have a linear and a constant term.