let g(x) = x² + 2x + k and p(x) = 2x⁴ + x³ - 14x² + 5x + 6

Then if g(x) is a factor of p(x)

By division algorithm

Dividend = (divisor) (quotient) + remainder

⇒ p(x) = g(x).q(x) + r(x)

Where q(x) is the quotient and

r(x) is the remainder which will be equal to zero.

i.e. r(x) = 0

Clearly q(x) = 2x² - 3x - 8 - 2k and r(x) = (21 + 7k)x + (2k² + 8k + 6) = 0

By comparing the coefficients, 21 + 7k = 0 and 2k² + 8k + 6 = 0

2k² + 8k + 6 = 0

k² + 4k + 3 = 0

k² + (k + 3k) + 3 = 0

k (k + 1) + 3(k + 1) = 0

(k + 1)(k + 3) = 0

⇒ k = - 1, - 3

Also, 21 + 7k = 0

Case1: k = - 1

21 + 7(- 1) = 0

= 21 - 7 = 14≠0

Hence k = - 1 is rejected.

Case2: k = - 3

21 + 7(- 3) = 0

= 21 - 21 = 0

∴ the value of k is - 3

g(x) = x² + 2x - 3

x² + 2x - 3 = 0

x² + (- x + 3x) - 3 = 0

x(x - 1) + 3(x - 1) = 0

(x - 1)(x + 3) = 0

⇒ x = 1, - 3

q(x) = 2x² - 3x - 8 - 2(- 3)

= 2x² - 3x - 2

2x² - 3x - 2 = 0

2x² - (4x - x) - 2 = 0

2x(x - 2) + (x - 2) = 0

(x - 2)(2x + 1) = 0

⇒ x = 2, - 1/2

Now, we know g(x) and q(x) are factors of p(x)

∴ the zeroes of g(x) and q(x) will be the zeroes of p(x)

Hence, the zeroes of p(x) = - 3, - 1/2, 1, 2