Write an equation of a line passing through the point representing solution of the pair of linear equations x + y = 2 and 2x-y = 1 How many such lines can we find?
Given pair of linear equations is
x + y-2 = 0 …(i)
and 2x-y-1 = 0 …(ii)
On comparing with ax + by + c = 0
Here, a1 = 1, b1 = 1, c1 = - 2;
And a2 = 2, b2 = - 1, c2 = - 1;
a1 /a2 = 1/2
b1 /b2 = - 1
c1 /c2 = 2
since a1/a2 b1/b2
So, both lines intersect at a point. Therefore, the pair of equations has a unique solution. Hence, these equations are consistent.
Now, x + y = 2 or y = 2-x
If x = 0 then y = 2 and if x = 2 then y = 0
x |
0 |
2 |
y |
2 |
0 |
Points |
A |
B |
and
If x = 0 then y = - 1 if x = then y = 0 and if x = 1 then y = 1
x |
0 |
1/2 |
1 |
y |
- 1 |
0 |
1 |
Points |
C |
D |
E |
Plotting the points A (2,0) and B(0,2), we get the straight line AB. Plotting the points C(0,- 1) and D(1/2, 0), we get the straight line CD.
The lines AB and CD intersect at E (1, 1).
Hence, infinite lines can pass through the intersection point of linear equations and i.e. E (1, 1) like as y = x, x + 2y = 3, x + y = 2 and so on.