Two numbers are in the ratio 5:6. If 8 is subtracted from each of the numbers, the ratio becomes 4:5, then find the numbers.

Let the two numbers be x and y.

Then, by first condition, ratio of these two numbers = 5 :6

and by second condition, then, 8 is subtracted from each of the numbers, then ratio becomes 4:5

=

5x – 4y = 8

Now, put the value of y in Eq. (ii), we get

5x – 4 ( ) = 8

So

And x = 40

Put the value of x in Eq. (i), we get

So, y = = 48

Hence, the required numbers are 40 and 48.

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