Draw the graphs of the equations, x = 3, x = 5 and 2x - y - 4 = 0. Find the area of the quadrilateral formed by the lines and the X - axis.

Given equation of lines x = 3, x = 5 and 2x-y-4 = 0.

Now, the table for line 2x - y - 4 = 0

for x = 0, y = - 4 and for y = 0, x = 2

0 | 2 | |

| - 4 | 0 |

Points | P | Q |

Draw the points P(0, - 4) and Q(2, 0) and join these points and form a line PQ also draw the lines x = 3 and x = 5.

Area of Quadrileral ABCD = 1/2×(distance between parallel lines)

[since, quadrilateral ABCD is a trapezium]

{since AB = OB-OA = 5-3 = 2, AD = 2 and BC = 6}

= 8 sq units

3