A shopkeeper sells a saree at 8% profit and a sweater at 10% discount, thereby, getting a sum ₹ 1008. If she had sold the saree at 10% profit and the sweater at 8% discount, she would have got ₹ 1028 then find the cost of the saree and the list price (price before discount) of the sweater.

Let the cost price of the saree and the list price of the sweater be ₹ x and ₹ y, respectively.

**Case I** Sells a saree at 8% profit + Sells a sweater at 10% discount = ₹ 1008

…(i)

**Case II** Sold the saree at 10% profit + Sold the sweater at 8% discount = ₹ 1028

(100 + 10)% of x + (100-8%) of y = 1028

110% of x + 92% of y = 1028

1.10x + 0.92 y = 1028 …(ii)

On putting the value of y from Eq. (i) into Eq. (ii), we get

1.1 × 0.9x + 0.92 × (1008-1.08x) = 1028×0.9

0.99x-0.9936x = 9252-927.36

-0.0036x = -2.16

On putting the value of x in Eq. (i), we get

Hence, the cost price of the saree and the list price (price before discount) of the sweater are ₹ 600 and ₹ 400, respectively.

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