Find a natural number whose square diminished by 84 is equal to thrice of 8 more than the given number.
Let the natural number be x,
Square of a number and diminished by 84
= (x2 + 84)
Thrice of 8 more than the given number
= 3(x + 8)
Equating both the equations,
⇒ x2 – 84 = 3(x + 8)
⇒ x2 – 84 = 3x + 24
∴ x2 - 3x – 108 = 0
Using the quadratic formula,
∴ The natural number . (* A natural number cannot be negative)