If the first term of an AP is - 5 and the common difference is 2, then the sum of the first 6 terms is
Given,
First term, a = - 5
Common Difference, d = 2
Where Sn is the sum of first n terms
n = no of terms
a = first term
d = common difference
S4 = (6/2)[ 2 (- 5) + (6 - 1)2]
= 3 (- 10 + 10)
= 0