Justify whether it is true to say that the following are the nth terms of an AP.
2n – 3
Put n = 1, 2, 3, 4
We get
a1 = 2(1) - 3 = - 1
a2 = 2(2) - 3 = 1
a3 = 2(3) - 3 = 3
a4 = 2(4) - 3 = 5
List of AP is - 1, 1, 3, 5 . . . .
a2 - a1 = 1 - (- 1) = 2
a3 - a2 = 3 - 1 = 2
a4 - a3 = 5 - 3 = 2
which form an AP, with common difference , d = 2