The angles of a triangle are in AP. The greatest angle is twice the least. Find all the angles of the triangle.
Let A, B and C be the three angles in AP (in degrees)
And A being the least and C being the greatest
Then
C = 2A [ Given][ eqn i]
B - A = C - B
2B = A + C
2B = A + 2A [ using eqn i]
2B = 3A
B = [ eqn ii]
Using the angle sum property of triangle
A + B + C = 180O
[ using i and ii]
9A = 360
A = 40O
[ using ii]
C = 2(40) = 80O [ using i]