Find the sum of the two middle most terms of an AP
Here,
first term, a =
common difference, d
last term, an = 4 =
using the nth term formula
an = a + (n - 1)d
13 = - 4 + (n - 1) [ multiplication by 3 on the both side]
13 + 4 = n - 1
n = 18
as n is even middle terms will be
a9 + a10 = a + 8d + a + 9d
= 2a + 17d