An AP consists of 37 terms. The sum of the three middle most terms is 225 and the sum of the last three terms is 429. Find the AP.
Let the a be first term and d be common difference of an AP
As n = 37 (odd)
Middle term will be
Three middle most terms will be
18th, 19th and 20th terms
Given,
a18 + a19 + a20 = 225
a + 17d + a + 18d + a + 19d = 225 [ using an = a + (n - 1)d]
3a + 54d = 225
3a = 225 - 54d
a = 75 - 18d [ eqn 1]
Also last three terms will be 35th , 36th and 37th terms
Given,
a35 + a36 + a37 = 429
a + 34d + a + 35d + a + 36d = 429
3a + 105d = 429
a + 35d = 143
75 - 18d + 35d = 143 [ using eqn1]
17d = 68
d = 4
using this value in eqn 1
a = 75 - 18(4)
a = 3
so AP is a, a + d, a + 2d….
i.e. 3, 7, 11….