The points (- 4, 0), (4, 0) and (0, 3) are the vertices of a

Let’s take;

A (- 4, 0),

B (4, 0),

C (0, 3) are the given vertices.

Now,

To calculate the distance between two given points;

Us the formula;

d^{2} = (x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

d =

So, the distance between point A and point B;

AB =

AB =

AB = 8

Distance between B (4, 0) and C (0, 3);

BC =

BC =

BC = 5

Distance between A (- 4, 0) and C (0, 3);

AC =

AC =

AC = 5

So, BC = AC

Hence, we can say that ΔABC is an isosceles triangle because an isosceles triangle has two sides equal.

9