The point which divides the line segment joining the points (7, - 6) and (3, 4) in ratio 1:2 internally lies in the

Let’s take A and B the joining point and P is the dividing point;

Let’s assume the co - ordinates of point P = x and y

By using Section formula;

x co - ordinate of point P will be -

x = and

y co - ordinate of point P will be -

∴ x =

Given that,

x_{1} = 7, y_{1} = - 6,

x_{2} = 3, y_{2} = 4

m = 1 and

n = 2

So, (x, y) = lies in IV quadrant.

[Since, in IV quadrant, x - coordinate is positive and y - coordinate is negative]

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