The area of a triangle with vertices (a, b + c), (b, c + a) and (c, a + b) is

Let the vertices of a triangle = A, B and C

Where;


A = (x1, y1) = (a, b + c)


B = (x2, y2) = (b, c + a) and


C = (x3, y3) = (c, a + b)


Area of


[x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]



[a(c - b) + b(a - c) + c(b - a)]


[ac - ab + ab - bc + bc - ac] = (0) = 0


Hence, the area of triangle is 0.

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