If the distance between the points (4, p) and (1, 0) is 5, then the value of p is

Given,


The distance between the points (4, p) and (1, 0) = 5


 


By using the formula of distance,


 



 


We get;


 



 


Distance between the points (x1, y1) and (x2, y2)


 



 



 


On squaring both the sides, we get


 


9 + p2 = 25


 


p2 = 16 p = ± 4


 


Hence, the required value of p is ± 4

19