Find the value of a, if the distance between the points A( - 3, - 14) and B(a, - 5) is 9 units.

According to the question,

Distance between AB = 9

Coordinates of A ( - 3, - 14)

Coordinates of B (a, - 5)

Distance between two points (x_{1}, y_{1}) and (x_{2}, y_{2});

d =

So,

AB = = 9

AB = = 9

On squaring both the sides,

We get;

(a + 3)^{2} + 81 = 81

(a + 3)^{2} = 0

A = - 3

Hence, the value of a is - 3.

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