The angle of elevation of the top of a tower from two points distant s and t from its foot are complementary. Prove that the height of the tower is .
Let BC = s; PC = t
Let height of the tower be AB = h.
∠ABC = θ and ∠APC = 90° - θ
(∵ the angle of elevation of the top of the tower from two points P and B are complementary)
In
In
Multiplying eq. 1 and eq. 2, we get
⇒ h2 = st
⇒ h = √st
Hence the height of the tower is √st.