Given radius(AO) = 13cm

Length of the chord (AB) = 10cm

Draw a perpendicular bisector from center to the chord and name it OC.

AC = BC = 5cm

Now in ∆ AOC,

Using Pythagoras theorem

AO² = AC² + OC²

13² = 5² + OC²

OC² = 13² – 5²

OC² = 169 – 25

OC² = 144

OC = 12cm

The distance of the chord from the centre is 12cm.