In the given figure, AOB is a diameter of a circle with centre O such that AB = 34 cm and CD is a chord of length 30 cm. Then, the distance of CD from AB is

Question

Philoid · Accepted Answer

Given: AB 34 cm and CD = 30 cm

Here OL is the perpendicular bisector to CD

∴ CL = LD = 15 cm

Construction: Join OD(radius)

OD = 17cm

Now in Δ ODL

By Pythagoras theorem

OD² = OL² + LD²

17² = OL² + 15²

OL² = 17² + 15²

OL² = 289—225

OL² = 64

OL = 8

∴The distance of from is = OL = 8cm