In the given figure, O is the centre of a circle. Then, ∠OAB = ?
Given: and
In ΔOAB
Here,
OA = OB (radius)
Let ∠OBA = ∠OAB = x (angles opposite to equal sides are equal)
By angle sum property
∠AOB + ∠OBA + ∠OAB = 180°
50° + x + x = 180°
2x = 180° – 50°
2x = 130°
x = 60°
∴ ∠OAB = 60°