In the given figure, O is the centre of a circle and AOB = 140°. Then, ACB = ?

Given: AOB = 140°


Here,


(Exterior AOB) = 360° – (interior AOB)


(Exterior AOB) = 360° – 140°


(Exterior AOB) = 220°


We know that,


(Exterior AOB) = 2 × ACB


220° = 2 × ACB


ACB = = 110°


ACB = 110°

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