The question consists of two statements, namely, Assertion (A) and Reason (R). For selecting the correct answer:
Assertion (A) | Reason (R) |
The circle drawn taking any one of the equal sides of an isosceles right triangle as diameter bisects the base. | The angle in a semicircle is 1 right angle. |
Assertion (A):
Construction: Draw a Δ ABC in which AB = AC, Let O be the midpoint of AB and with O as centre and OA as radius draw a circle, meeting BC at D
Now, In Δ ABD
∠ ADB = 90° (angle in semicircle)
Also, ∠ ADB + ∠ ADC = 180°
90° + ∠ ADC = 180°
∠ ADC = 180° – 90°
∠ ADC = 90°
Consider Δ ADB and Δ ADC
Here,
AB = AC (given)
AD = AD (common)
∠ ADB = ∠ ADC ( 90° )
∴ By SAS congruency, Δ ADB Δ ADC
So, BD = DC(C.P.C.T)
Thus, the given circle bisects the base. So, Assertion (A) is true
Reason (R) :
Let ∠ BAC be an angle in a semicircle with centre O and diameter BOC
Now, the angle subtended by arc BOC at the centre is ∠ BOC = 2× 90°
∠ BOC = 2× ∠ BAC = 2× 90°
So, ∠ BAC = 90° (right angle)
So, reason (R) is true
Clearly, reason (R) gives assertion (A)
Hence, correct choice is A