In the given figure, ECB = 40° and CEB = 105°. Then, EAD = ?

Given: and


Here,


ACB = ADB = 40° (angles in same segment)


BEC = AED = 105° (vertically opposite angles)


In ΔAED


By angle sum property


ADE + AED + EAD = 180°


40° + 105° + EAD = 180°


EAD = 180° – 40° – 105° = 35°


EAD = 35°

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