In the given figure, ∠ECB = 40° and ∠CEB = 105°. Then, ∠EAD = ?
Given: and
Here,
∠ACB = ∠ADB = 40° (angles in same segment)
∠BEC = ∠AED = 105° (vertically opposite angles)
In ΔAED
By angle sum property
∠ADE + ∠AED + ∠EAD = 180°
40° + 105° + ∠EAD = 180°
∠EAD = 180° – 40° – 105° = 35°
∴ ∠EAD = 35°