In the given figure, AOC is a diameter of a circle with centre O and arc arc BYC. Find ∠BOC.
Given: arc
Here,
2×AXB = BYC
∴ 2×∠AOB = ∠BOC
∠AOB = ∠BOC –1
Here,
∠AOC = ∠AOB + ∠BOC = 180°
∠BOC + ∠BOC = 180° (from –1)
∠BOC = 180°
∠BOC = ×180° = 120°
∴