In the given figure, O is the centre of a circle, OAB = 30° and OCB = 55°. Find BOC and AOC.

Given: and


Here,


In ΔAOB


OA = OB (radius)


OAB = OBA (angles opposite to equal sides are equal)


OBA = 30°


Now, by angle sum property


AOB + OBA + OAB = 180°


AOB + 30° + 30° = 180°


AOB = 180° – 30° – 30°


AOB = 120°


Now, Consider Δ BOC


OC = OB (radius)


OCB = OBC (angles opposite to equal sides are equal)


OBA = 55°


Now, by angle sum property


BOC + OBC + OCB = 180°


BOC + 55° + 55° = 180°


BOC = 180° – 55° – 55° = 70°


BOC = 70°


Here,


AOB = AOC + BOC


120° = AOC + 70°


AOC = 120° 70°


AOC = 50°


AOC = 50°



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