In the given figure, AOB is a diameter of the circle and C, D, E are any three points on the semicircle. Find the value of ∠ACD + ∠BED.
Construction: Join AE
Consider cyclic quadrilateral ACDEA
Here,
∠ACD + ∠DEA = 180° (opposite angles in cyclic quadrilateral are supplementary)
Also,
∠AEB = 90° (angle in semicircle)
∴∠ACD + ∠DEA + ∠AEB = 180° + 90°
∠ACD + ∠BED = 270° (∠DEA + ∠AEB = ∠BED)
∴∠ACD + ∠BED = 270°
Hence proved.