In figure, if ∠AOB = 125°, then ∠COD is equal to
As in the given figure ABCD is a quadrilateral circumscribing the circle and we know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the center of the circle.
So, we have
∠AOB + ∠COD = 180°
125° + ∠COD = 180°
∠COD = 55°