If two tangents inclined at an angle 60° are drawn to a circle of radius 3 cm, then the length of each tangent is

Given : A circle with center O and PA and PB are two tangents to the circle at point A and C from an external point P such that APC = 60° [i.e. angle of inclination between two tangents] .

To Find : AP and PC

In OAP and OCP

AO = OC [ radii of same circle]

OP = OP [ common ]

AP = PC [ tangents through an external point to a circle are equal]

OAP OPC [ By Side Side Criterion]

APO = OPC [Corresponding parts of congruent triangles are equal] [1]

Now, APC = 60° [Given]

APO + OPC = 60°

APO + APO = 60° [By 1]

2AP0 = 60°

APO = 30°

Now, OA AP [ As tangent at any point on the circle is perpendicular to the radius through point of contact]

OAP = 90°

So AOP is a right-angled triangle

And we know that,


[As OA is radius and equal to 3 cm]