A chord PQ of a circle is parallel to the tangent drawn at a point R of the circle. Prove that R bisects the arc PRQ.
PQ is a chord in a circle with center O and MN is a tangent drawn at point R on the circle PQ is parallel to MN
To Prove : R bisects the arc PRQ i.e. arc PR = arc PQ
Proof :
∠1 = ∠2 [Alternate Interior angles]
∠1 = ∠3 [angle between tangent and chord is equal to angle made by chord in alternate segment]
So, we have
∠2 = ∠3
QR = PR [Sides opposite to equal angles are equal]
As the equal chords cuts equal arcs in a circle.
Arc PR = arc RQ
R bisects the arc PRQ .
Hence Proved