In a quadrilateral ABCD, it is given that BD = 16cm. If AL ⊥ BD and CM ⊥ BD such that AL = 9cm and CM = 7cm, then ar(quad.ABCD) = ?
Given:
BD = 16cm
AL ⊥ BD
CM ⊥ BD
AL = 9cm
CM = 7cm
Here,
Area of quadrilateral ABCD = area(ΔABD) + area(ΔBCD)
Area of triangle = 1/2 × base × height
area(ΔABD) = 1/2 × base × height = 1/2 × BD × CM = 1/2 × 16 × 7 = 56cm2
area(ΔBCD) = 1/2 × base × height = 1/2 × BD × AL = 1/2 × 16 × 9 = 64cm2
∴ Area of quadrilateral ABCD = area(ΔABD) + area(ΔBCD) = 56 + 64 = 120cm2