In a quadrilateral ABCD, it is given that BD = 16cm. If AL BD and CM BD such that AL = 9cm and CM = 7cm, then ar(quad.ABCD) = ?

Given:


BD = 16cm


AL BD


CM BD


AL = 9cm


CM = 7cm


Here,


Area of quadrilateral ABCD = area(ΔABD) + area(ΔBCD)


Area of triangle = 1/2 × base × height


area(ΔABD) = 1/2 × base × height = 1/2 × BD × CM = 1/2 × 16 × 7 = 56cm2


area(ΔBCD) = 1/2 × base × height = 1/2 × BD × AL = 1/2 × 16 × 9 = 64cm2


Area of quadrilateral ABCD = area(ΔABD) + area(ΔBCD) = 56 + 64 = 120cm2

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