In ∆ABC, it given that D is the midpoint of BC; E is the midpoint of BD and O is the midpoint of AE. Then ar(∆BOE) = ?

Given: D is the midpoint of BC; E is the midpoint of BD and O is the midpoint of AE.


Here,


D is the midpoint of BC and AD is the median of ΔABC


Area (Δ ABD) = Area (Δ ADC) ( median divides the triangle into two triangles of equal areas)


Area (Δ ABD) = Area (Δ ADC) = Area (∆ABC)


Now, consider Δ ABD


Here, AE is the median


Area (Δ ABE) = Area (Δ BED)


Area (Δ ABE) = Area (Δ BED) = Area (∆ABD)


Area (Δ ABE) = Area (∆ABD)


Area (Δ ABE) = × (Area (Δ ABD) = Area (∆ABC) ) –1


Area (Δ ABE) = Area (∆ABC)


Consider Δ ABE


Here, BO is the median


Area (Δ BOE) = Area (Δ BOA)


Area (Δ BOE) = Area (Δ BOA) = Area (∆ABE)


Area (Δ BOE) = × (Area (Δ ABE) = Area (∆ABC) )


Area (Δ BOE) = Area (∆ABC)


Area (Δ BOE) = Area (∆ABC)

21