In ∆ABC, it given that D is the midpoint of BC; E is the midpoint of BD and O is the midpoint of AE. Then ar(∆BOE) = ?
Given: D is the midpoint of BC; E is the midpoint of BD and O is the midpoint of AE.
Here,
D is the midpoint of BC and AD is the median of ΔABC
Area (Δ ABD) = Area (Δ ADC) (∵ median divides the triangle into two triangles of equal areas)
∴ Area (Δ ABD) = Area (Δ ADC) = Area (∆ABC)
Now, consider Δ ABD
Here, AE is the median
Area (Δ ABE) = Area (Δ BED)
∴ Area (Δ ABE) = Area (Δ BED) = Area (∆ABD)
Area (Δ ABE) = Area (∆ABD)
Area (Δ ABE) = ×
(∵Area (Δ ABD) =
Area (∆ABC) ) –1
Area (Δ ABE) = Area (∆ABC)
Consider Δ ABE
Here, BO is the median
Area (Δ BOE) = Area (Δ BOA)
∴ Area (Δ BOE) = Area (Δ BOA) = Area (∆ABE)
Area (Δ BOE) = ×
(∵Area (Δ ABE) =
Area (∆ABC) )
Area (Δ BOE) = Area (∆ABC)
∴ Area (Δ BOE) = Area (∆ABC)