If a triangle and a parallelogram are on the same base and between the same parallels, then the ratio of the area of the triangle to the parallelogram is
Given:
We know that when a parallelogram and a triangle lie on same base and between same parallel lines then, area of the triangle is half the area of the parallelogram.
Area (ΔABF) = 1/2 Area(||gm ABCD) –1
Area (ΔABF) : Area (||gm ABCD) = 1/2 Area(||gm ABCD) : Area(||gm ABCD) (from –1 )
Area (ΔABF) : Area (||gm ABCD) = 1/2 : 1 = 1:2
∴ Area (ΔABF) : Area (||gm ABCD) = 1:2