Let ABCD be a gm in which DL AB and BM AD such that AD = 6 cm, BM = 10 and DL = 8 cm. Find AB.

Given:


AD = 6cm


DL AB


BM AD


DL = 8cm


BM = 10cm


Now, consider the parallelogram ABCD


Here, let AD be the base of the parallelogram then BM becomes its altitude (height).


Area of the parallelogram is given by: Base × Height


area of gm ABCD = AD×BM = 6×10 = 60cm2


Now,


Consider AB as base of the parallelogram then DL becomes its altitude (height)


area of gm ABCD = AB × DL = 60cm2


AB × 8 = 60cm2


AB = = 7.5cm


length of AB = 7.5cm.


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