Let ABCD be a ‖ gm in which DL ⊥ AB and BM ⊥ AD such that AD = 6 cm, BM = 10 and DL = 8 cm. Find AB.
Given:
AD = 6cm
DL ⊥AB
BM ⊥ AD
DL = 8cm
BM = 10cm
Now, consider the parallelogram ABCD
Here, let AD be the base of the parallelogram then BM becomes its altitude (height).
Area of the parallelogram is given by: Base × Height
∴ area of ‖gm ABCD = AD×BM = 6×10 = 60cm2
Now,
Consider AB as base of the parallelogram then DL becomes its altitude (height)
∴ area of ‖gm ABCD = AB × DL = 60cm2
AB × 8 = 60cm2
AB = = 7.5cm
∴length of AB = 7.5cm.