We are given that

Circumference of a circle = Perimeter of square

Let r be the radius of the circle and a be the side of square.

∴ from the given condition, we have 2π r = 4a

(22/7)r = 2a

⇒ 11r = 7a

⇒ a = (11/7)a

⇒ r = (7/11)a …………..(i)

Now, area of circle = A₁ = πr² and area of square = A₂ = a²

From equation (i ), we have

A₁ = π × (7/11)²

= (22/7) × (49/121)a²

= (14/11)a² and A₂ = a²

∴ A₁ = (14/11) A₂

⇒ A₁ > A₂

Hence, Area of the circle > Area of the square.