The graph of the linear equation 4x + 3y = 12 cuts the x-axis at the point
4x + 3y = 12
⇒ 3y = 12 – 4x
When x = 0, then,
When x = 3, then,
⇒ y = 0
Thus, we have the following table,
X | 0 | 3 |
Y | 4 | 0 |
Plotting these points we have the following graph,
The blue line in the graph is the required line of the equation, 4x + 3y = 12
According to the graph, the equation,
4x + 3y = 12 cuts the x-axis at the point (3, 0)