The graph of the linear equation 4x + 3y = 12 cuts the x-axis at the point

4x + 3y = 12


3y = 12 – 4x



When x = 0, then,






When x = 3, then,




y = 0


Thus, we have the following table,


X



0



3



Y



4



0



Plotting these points we have the following graph,



The blue line in the graph is the required line of the equation, 4x + 3y = 12


According to the graph, the equation,


4x + 3y = 12 cuts the x-axis at the point (3, 0)

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