(i) x = – 2

⇒ x + 2 = 0

Comparing, x + 2 = 0 with ax + by + c = 0 we get,

the coefficient of x i.e., a = 1

and the coefficient of y i.e., b = 0 since, there is no term of y

and clearly, c = 2

putting the values of a, b and c in ax + by + c = 0 we get,

x + 0×y + 2 = 0

(ii) y = 6

⇒ y – 6 = 0

Comparing, y – 6 = 0 with ax + by + c = 0 we get,

the coefficient of x i.e., a = 0 since, there is no term of x

and the coefficient of y i.e., b = 1

and clearly, c = – 6

putting the values of a, b and c in ax + by + c = 0 we get,

0×x + y – 6 = 0