Draw the graph of the equation 3x + 2y = 12. At what points does the graph cut the x-axis and the y-axis?
3x + 2y = 12
⇒ 3x + 2y = 12
⇒ 2y = 12 – 3x
When, x = 0 then,
⇒ y = 6
When, x = 4 then,
⇒ y = 0
On plotting, (0, 6) and (4, 0) we get the following graph,
The blue line indicates the required graph of 3x + 2y = 12
It can be clearly seen from the graph, that it cuts the x axis at (4, 0) and y axis at (0, 6)
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