A student says that, if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting not 1 each is equal to Is this correct? Give reasons.

No, this is not correct.

Suppose we throw a die, then total number of outcomes = 6

Possible outcomes = 1or 2or 3or 4or 5or 6

∴ Probability of getting 1 = 1/6

Now, probability of getting not 1 = 1 – Probability of getting 1

= 1 - 1/6 = 5/6

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