A student says that, if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting not 1 each is equal to 
Is this correct? Give reasons.
No, this is not correct.
Suppose we throw a die, then total number of outcomes = 6
Possible outcomes = 1or 2or 3or 4or 5or 6
∴ Probability of getting 1 = 1/6
Now, probability of getting not 1 = 1 – Probability of getting 1
= 1 - 1/6 = 5/6
9