Two dice are thrown at the same time and the product of numbers appearing on them is noted. Find the probability that the product is less than 9.
Number of total outcomes = 36
When product of numbers appearing on them is less than 9, then possible ways are (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1), (2, 2), (2, 3), (2, 4), (3, 2), (4, 2), (4, 1), (3, 1), (5, 1), (6, 1) and (2, 1).
Number of possible ways = 16
∴ Required probability = 16/36 = 4/9