Two dice are numbered 1, 2, 3, 4, 5, 6 and 1, 1, 2, 2, 3, 3, respectively. They are thrown and the sum of the numbers on them is noted. Find the probability of getting each sum from 2 to 9, separately.

Number of total outcome = n(S) = 36

(i) Let E1 = Event of getting sum 2 = {(1,1),(1,1)}


n(E1) = 2




(ii) Let E2 = Event of getting sum 3 = {(1,2),(1,2),(2,1),(2,1)}


n(E2) = 4



(iii) Let E3 = Event of getting sum 4 = {(2,2)(2,2),(3,1),(3,1),(1,3),(1,3)}


n(E3) = 6



(iv) Let E4 = Event of getting sum 5 = {(2,3),(2,3),(4,1),(4,1),(3,2),(3,2)}


n(E4) = 6



(v) Let E5 = Event of getting sum 6 = {(3,3),(3,3),(4,2),(4,2),(5,1),(5,1)}


n(E5) = 6



(vi) Let E6 = Event of getting sum 7 = {(4,3),(4,3),(5,2),(5,2),(6,1),(6,1)}


n(E6) = 6



(vii)Let E7 = Event of getting sum 8 = {(5,3),(5,3),(6,2),(6,2)}


n(E7) = 4



(viii)Let E8 = Event of getting sum 9 = {(6,3),(6,3)}


n(E3) = 2



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