Two dice are numbered 1, 2, 3, 4, 5, 6 and 1, 1, 2, 2, 3, 3, respectively. They are thrown and the sum of the numbers on them is noted. Find the probability of getting each sum from 2 to 9, separately.

Number of total outcome = n(S) = 36

(i) Let E_{1} = Event of getting sum 2 = {(1,1),(1,1)}

n(E_{1}) = 2

(ii) Let E_{2} = Event of getting sum 3 = {(1,2),(1,2),(2,1),(2,1)}

n(E_{2}) = 4

(iii) Let E_{3} = Event of getting sum 4 = {(2,2)(2,2),(3,1),(3,1),(1,3),(1,3)}

n(E_{3}) = 6

(iv) Let E_{4} = Event of getting sum 5 = {(2,3),(2,3),(4,1),(4,1),(3,2),(3,2)}

n(E_{4}) = 6

(v) Let E_{5} = Event of getting sum 6 = {(3,3),(3,3),(4,2),(4,2),(5,1),(5,1)}

n(E_{5}) = 6

(vi) Let E_{6} = Event of getting sum 7 = {(4,3),(4,3),(5,2),(5,2),(6,1),(6,1)}

n(E_{6}) = 6

(vii)Let E_{7} = Event of getting sum 8 = {(5,3),(5,3),(6,2),(6,2)}

n(E_{7}) = 4

(viii)Let E_{8} = Event of getting sum 9 = {(6,3),(6,3)}

n(E_{3}) = 2

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